Remove Duplicates from Sorted Array

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example 1:

Given *nums* = **[1,1,2]**,

Your function should return length = **`2`**, with the first two elements of *`nums`* being **`1`** and **`2`** respectively.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given *nums* = **[0,0,1,1,1,2,2,3,3,4]**,

Your function should return length = **`5`**, with the first five elements of *`nums`* being modified to **`0`**, **`1`**, **`2`**, **`3`**, and **`4`** respectively.

It doesn't matter what values are set beyond the returned length.

class Solution:
    def removeDuplicates(self, nums: List[int]):
        if not nums:
            return 0

        newTail = 0

        for i in range(1, len(nums)):
            if nums[i] != nums[newTail]:
                newTail += 1
                nums[newTail] = nums[i]

        return newTail + 1

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